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How much current do those things draw, and how many bulbs are in there?It might be possible to wire a resistor into the circuit in each car so the would burn nicelyon your track voltage. But the current draw is probably high enough that it would require a bigresistor that will give off a lot of heat. Even a 1W resistor is cumbersome in size and makes a lot of heat.You could use a pair of 1/2W to spread out the footprint and the heat, I suppose.
Peteski, the reason I proposed using two resistors in parallel is that they could be spaced apart (not like 1/8" apart, like at opposite ends of the car or something) just to spread the heat, rather than have it all concentrated at one point near a plastic part of the shell.So, OldEastRR, there is only one bulb? Really?Can you measure the current draw of one car please?I'll take a leap and guess it's a typical 60ma grain of wheat bulb. If you want to knock off 6v,6 / .060 = 100 ohm. 6 x .060 = 360 mW So a 1/2 watt 100 ohm resistor will do it. But if the current draw is higher, your DCC track voltage is high enough that you need to knock off more than 6v, or you have 2 bulbs, that resistor wattage is going to go up, of course, so we really need that current draw and an accurate measure of the DCC track voltage if you even want to attempt this.
Hi Max. Your numbers are an excellent guess. Information on the web indicates that those bulbs are 12v, 60ma. But if you're dimming them by reducing voltage using a resistor, aren't you also likely reducing the current passing through the bulb?And by the way, if Old East is correct that his DCC system is putting out 22v to the track, then you're dropping 15v, and 15v at 60ma is .9 watts, so you'd need a 1-watt resistor in that case. That's a lot of heat. If the DCC system really is putting out 22v, he needs to find a way to adjust that down to something reasonable, like 13v (or even lower for N scale; I use 11.5v).John C.